(iv) Join SB. (x) Is 45° the supplement of 45°? Find the unknown angles. (ii) Mark a point A on PQ so that AP = 2 cm. Then ∠ABC = 15°. Also, a line segment is the shortest distance between two fixed points. In which of the following figures, are ∠AOB and ∠AOC adjacent angles? NCERT Solutions for Class 7 Mathematics CBSE, 5 Lines And Angles. Question 2. (ii) A ray has one end point and a line segment has two end-points. Write the supplement of: (i) 100° (ii) 0° (iii) x° (iv) (x + 35)° (v) (90 +a + b)° f (vi) (110 – x – 2y)° (vii) $$\frac { 1 }{ 5 }$$ of a right angle (viii) 80° 49′ 25″ Solution: Question 12. In questions 1 and 2, given below, identify the given pairs of angles as corresponding angles, interior alternate angles, exterior alternate angles, adjacent angles, vertically opposite angles or allied angles : (i) ∠3 and ∠6 ∴ Lines are parallel. In the given figures, the directed lines are parallel to each other. Question 3. (ii) Find a, if x = 3a, y = 5x and r = 6x. Give reason: In the given figures, the directed lines are parallel to each other. (iii) x° (iv) Taking P and Q as curves, draw two arcs intersecting each other at D nnd join BD. (vi) 22.5° Draw its perpendicular bisector. (iv) 180° (ii) With centre B and some suitable radius, draw an arc meeting BC at P. (iii) With centre P and some radius, cut off arcs PQ. If x : y = 1 : 2 and z = 90°, find ∠ROM and ∠POR. In the adjoining figure, two straight lines AB and CD intersect each other at point 0. (i) Find x, if y = 45° and z = 90°. (ii) ∠2 and ∠4 ANGLE : An angle is formed when two line segments or two rays have a common end-point. (iii) A line segment is the shortest distance between any two given points. Answer, In the given figure, find ∠AOB and ∠BOC. Bisect the angle using ruler and compasses only. It is clear from the figure, that a ray is a part of a line. Solution: If ∠AOB and ∠AOC are adjacent angle if they have OA their common arm. Clearly, 30″ is the supplement of 150° and vice-versa. 10. 12. Selina Class 7 Mathematics … Write the complement of: Solution: Question 11. ICSE Class 7 Selina solution: Lines and Angles Chapter 14. Our Solutions contain all type Questions with Exe-14 A , Exe-14 B,  and  Exe-14 C to develop skill and confidence. (i) Find x, if y = 45° and z = 90°. Mark a point P in AB such that PB = 3.6 cm. Exercise – 15 A Triangles ICSE Class-7th Concise Selina Mathematics Solutions Question 1. ∠1 = ∠5;∠2 = ∠6;∠3 = ∠7 and ∠4 = ∠8 (iii) Co-interior or allied angles are supplementary : i. e. ∠3 + ∠5 = 180° and ∠4 +∠6 = 180°. Extra Questions for Class 7 Maths Chapter 5 Lines and Angles. Draw a line segment AB = 8 cm. (viii) How many lines can be drawn through three (a) collinear points? (iv) Join BS and produce it to A. (iii) With centre Q and R, draw two arcs intersecting each other at S. (iv) Join SB. Answer, In the given figure, lines PQ, MN and RS intersect at O. (vii) ∠1 and ∠5 (C) Vertically opposite angles : When two straight lines intersect each other four angles are formed. Two pairs of allied or co-interior or conjoined angles : Angles marked 3 and 2 form one pair and angles marked 1 and 4 form another pair of allied angles. Answer, In the given figure, if x = 2y, find x and y (vi) 22.5° Steps of Construction : (i) Draw a line segment BC. Selina Publishers Concise Maths Class 7 ICSE Solutions Chapter 14 Lines and Angles (Including Construction of angles), ICSE SolutionsSelina ICSE SolutionsML Aggarwal Solutions. (iv) In this figure, OB is their common arm ∴ ∠AOB and ∠AOC are not adjacent angles. (ii) the complement of angle x. (vii) How many rays can be drawn through a fixed point O? Answer. Solution: Question 17. We provide step by step Solutions of Exercise / lesson-14 Lines and Angles (Including Construction of angles)  for  ICSE Class-7 Concise Selina Mathematics. Solution: Question 19. (v) ∠4 and∠6 (iv) ∠7 and ∠13 Question 2. Draw ∠ABC = 120°. Answer, In the adjoining figure, if b° = a° + c°, find b. (vii) ∠1 and ∠5 are corresponding angles. State Books Bihar UP Andhra Pradesh Chhattisgarh Gujarat Karnataka Kerala Madhya Pradesh Maharashtra Punjab Rajasthan Tamilnadu Telangana ICSE NIOS Odisha Board. (iv) ∠7 and ∠13 are corresponding angles. Answer, Construct an angle of 75° and then bisect it. We provide step by step Solutions of Exercise / lesson-14 Lines and Angles (Including Construction of angles) for ICSE Class-7 Concise Selina Mathematics. i. e. ∠AOD = ∠BOC and ∠AOC = ∠BOD. Solution: Question 16. (v) Join AB and produce it to R. Then ∠QAR = 60°, Question 4. Which pair of the dotted line, segments, in the following figures, are parallel. Solution: Steps of Construction : (i) Draw a line segment AB = 8 cm. (viii) How many lines can be drawn through three (v) With centre P and R, draw two more arcs intersecting each other at S. (vi) Join BS and produce it to A. Solution: Question 10. Answer, Draw ∠ABC = 120°. Solution: Question 9. Then ∠ABC = 75°. It, in general, is represented by a capital letter as shown alongside. Concepts covered in Lines and Angles (Including Construction of angles) are Concept for Pairs of Angles, Concept for Properties of Parallel Lines with Transversal, Construction of a Line Parallel to a Given Line from a Point Outside It ., Introduction to Lines and Angles . (ii) With centres A and B and with some suitable radius, draw arcs intersecting each other at S and R. (iii) Join SR intersecting AB at Q. Angles-An angle is formed when lines or line segments meet.-The lines that form an angle are called the sides or the arms of the angle.-The common end point is called the vertex of the angle.-The angle formed by two lines or line segments can be an acute angle, where the measure of the angle is less than 90°.-The angle formed by two lines or line segments can be a right angle… Answer, In the given figure, find the measure of the unknown angles : Yes, both angles are equal in measure. (iv) An infinite number of straight lines can be drawn through a given point. A line may be straight or curved but when we say a line’ it means a straight line only. (ii) True (iii) True (iv) True (v) (a) 2 (b) 1 (c) 0 (vi) AB (vii) Infinite (viii) (a) 1 (b) 3 (ix) False : 40° is the complement of 50° as 40° + 50° = 90° (x) False : 45° is the supplement of 135° not 45°. 1. At P, construct angle APQ = 30°. (x) ∠6 and ∠7 are adjacent angles. (v) Bisect arc QR at S and join BS. (ii) Mark a point P in AB such that AP = 5 cm. ∠3 = ∠6 and ∠4 = ∠5 [Interior alternate angles] ∠1 = ∠8 and ∠2 = ∠7 [Exterior alternate angles] (ii) Corresponding angles are equal: i.e. Acute angle : measures less than 90° 2. Question 3. (a) collinear points? Here, we are going to discuss the various types of angle, its measure, parallel lines angle formed using lines, etc. RAY : It is a straight line which stats from a fixed point and moves in the same direction. 5.1 … (vi) Out of  ,  ,  and  , which one has a fixed length? Solution. (ii) ∠4 and ∠7 (i) ∠3 and ∠6 (ii) ∠2 and ∠4 (iii) ∠3 and ∠7 (iv) ∠2 and ∠7 (v) ∠4 and∠6 (vi) ∠1 and ∠8 (vii) ∠1 and ∠5 (viii) ∠1 and ∠4 (ix) ∠5 and ∠7 Solution: (i) ∠3 and ∠6 are interior alternate angles. (i) 100° Draw its perpendicular bisector. Draw a line segment AB = 5.8 cm. Class 7 Mathematics Chapter 5 "Lines and Angles". Find : (i) x (ii) ∠AOB (iii) ∠BOC Solution: Question 4. (vii) ∠7 and ∠9 are vertically opposite angles. COMPLEMENTARY AND SUPPLEMENTARY ANGLES 1. (ii) At B, draw an angle ABC equal to 75°. Question 2. Lines and Angles Exercise 14B – Selina Concise Mathematics Class 7 ICSE Solutions In questions 1 and 2, given below, identify the given pairs of angles as corresponding angles, interior alternate angles, exterior alternate angles, adjacent angles, vertically opposite angles or allied angles : Question 1. Mark a point A in PQ so that AP = 2 cm. Thus, the supplement of 105° = 180° – 105° = 75°. 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